Linear Mixed Effect Modeling#

Note

This chapter written by Todd Gureckis who adapted it from Gabriela K Hajduk and the University of Edinburgh coding club tutorial on Mixed Effect Linear Models and the mixed models Kaggle notebook by OJ Watson. The former is release under CC BY-SA 4.0, the latter under the Apache 2.0 license. The text is a mashup of these two resources with various editing to connect to the rest of the book for the current class. The notebook released under the license for the book.

The goal in this chapter is to introduce linear mixed effect modeling (aka LME). Linear mixed effect models are among the most useful in psychological science. While previous chapters explore the virtues of linear modeling (e.g., linear regression), this chapter deals with a very common scenario where different observations might fall into various subgroups. For example, we might have data that are trials in an experiment which are grouped into which subject they came from. The subjects might be grouped by which condition of an experiment they were assigned to or how old they are. Linear mixed effect models are an useful tool for analyzing these types of data because they help to minimize the number of independent tests that are performed across groups (the multiple comparison problem) while also helping to ensure that the data is not broken into many small group (lowering power).

# import modules needed
%matplotlib inline
import matplotlib.pyplot as plt
import seaborn as sns; sns.set()
import numpy as np
import pandas as pd
import sklearn as sk
from math import sqrt
import warnings
warnings.filterwarnings('ignore')

class Caption:
    def __init__(self, fig_no, text, c_type='f'):
        self.fig_no = fig_no
        self.text = text
        if c_type=='t':
            self.c_type = 'Table'
        else:
            self.c_type = 'Figure'
    
    def _repr_html_(self):
        return f"<div class=\"alert alert-info\" role=\"alert\"><b>{ self.c_type } { self.fig_no }</b>. { self.text }</div>"

An case example: Bounce time from a website#

Rather than starting with a bunch of equations and terms lets just start with an intuitive example. We will start by analyzing a dataset (from Kaggle) that looks at the bounce times of users of a website with cooking recipes. The bounce time is a measure of how quickly someone leaves a website, e.g. the number of seconds after which a user first accesses a webpage from the website and then leaves. The phrase bounce is like when you are at a party and the cops show up: “let’s bounce.”

Most websites want individuals to stay on their websites for a long time as they are more likely to read another article, buy one of their products, click on some of the sponsored links etc. As such, it can be useful to understand why some users leave the website quicker than others.

To investigate the bounce time of the website, we chose three locations in 8 counties in England, and got members of the public of all ages to undertake a survey/test questionaire. In the test we asked them to use our search engine to query for something they want to eat this evening. The search engine listed our website first, as well as other websites that would be returned. The users that clicked on our website were then timed and their bounce time recorded. We also recorded their age, and made a note of the county and location.

We have been asked by the website to work out if younger individuals are more likely to leave the website quicker.

Let’s begin by reading in the data.

# read in our data
data = pd.read_csv('http://gureckislab.org/courses/spring20/labincp/data/bounce.csv')
data.head(15)
bounce_time age county location
0 165.548520 16 devon a
1 167.559314 34 devon a
2 165.882952 6 devon a
3 167.685525 19 devon a
4 169.959681 34 devon a
5 168.688747 47 devon a
6 169.619382 7 devon a
7 164.416273 8 devon a
8 167.510430 8 devon a
9 179.606068 7 devon a
10 174.465485 40 devon a
11 164.781248 38 devon a
12 172.559467 23 devon a
13 179.000774 7 devon a
14 175.970409 18 devon a

As we can see, there is the bounce time in seconds, the age of the person, the county they live in, and there is a location code for the place the person was recruited inside the county. Let’s take the approach of kind of exploring the data with descriptive statistics and plots to get a sense of what is going on.

# plot the distribution of the bounce times - this creates the object that will be plotted when matplotlib.pyplot
sns.distplot(data.bounce_time)
plt.show()
display(Caption(1.0, "Histogram showing how many seconds people spent on the website."))
../../_images/00-mixed-effect_6_0.png 
# plot the distribution of the ages
sns.distplot(data.age, kde=False)
plt.show()
display(Caption(2.0, "Histogram showing the ages of people who took part in the marketing study."))
../../_images/00-mixed-effect_7_0.png

Before we carry on it is often a good idea to scale our independent (explanatory) variables so that they are standardised. This is useful as it means that any estimated coefficient from our regression model later on are all on the same scale. So, for our dataset this would be the age, and let’s create a new variable called age_scaled, which is the age scaled to have zero mean and unit variance (the z-score):

# lets use the scale function from the preprocess package within sklearn
from sklearn import preprocessing
data["age_scaled"] = preprocessing.scale(data.age.values)

We discussed z-scores in a previous chapter including how to compute them in python. Here we use the scikit-learn package, a machine learning toolkit, which has a helpful scaling function built-in see here for full documentation.

This scaling won’t impact the statistical findings in our example but you may find in more complex models than the one in this tutorial this can be very helpful in speeding up your models fitting. It is also makes comparison between a continous variable like age, and a binary variable (0, 1) more fair.

# plot the scaled distribution
sns.distplot(data.age_scaled, kde=False)
plt.show()
display(Caption(3.0, "Histogram showing the z-scored ages of people who took part in the marketing study."))
../../_images/00-mixed-effect_11_0.png

Simple Linear Regression#

One thing we might want to do to see if the bounce time is dependent on the age is to plot this data, and then fit a linear regression to the data:

# let's use the lmplot function within seaborn
sns.lmplot(x = "age", y = "bounce_time", data = data)

<seaborn.axisgrid.FacetGrid at 0x12ec0a390>
../../_images/00-mixed-effect_14_1.png

It would seem, from this simple analysis that older people do spend longer time on the website. To go into this further let’s look at what the coefficients estimated are within our linear model.

Quick Review of Simple Linear Regression#

We will start with the most familiar linear regression, a straight-line fit to data. A straight-line fit is a model of the form

\[ y = b_0 + b_1x \]

where \(b_1\) is commonly known as the gradient, and \(b_0\) is commonly known as the intercept. So for our dataset, y would be the bounce time, x their age, b_1 the rate of change of the bounce time with respect to age and b_0 the intercept when age is 0.

\[ time = b_0 + b_1age \]

We can use Scikit-Learn’s LinearRegression estimator to fit this data and construct the best-fit line:

from sklearn.linear_model import LinearRegression

# construct our linear regression model
model = LinearRegression(fit_intercept=True)
x = data.age_scaled
y = data.bounce_time

# fit our model to the data
model.fit(x[:, np.newaxis], y)

# and let's plot what this relationship looks like 
xfit = np.linspace(-3, 3, 1000)
yfit = model.predict(xfit[:, np.newaxis])
plt.scatter(x, y)
plt.plot(xfit, yfit);
../../_images/00-mixed-effect_18_0.png

We can have a look at these parameters within the model object, with the relevant parameters being coef_ and intercept_:

print("Model slope:    ", model.coef_[0])
print("Model intercept:", model.intercept_)

Model slope:     6.279602007970818
Model intercept: 201.31646151854164

# and let's store the rmse
y_predict = model.predict(x.values.reshape(-1,1))
RMSE = sqrt(((y-y_predict)**2).values.mean())

results = pd.DataFrame()
results["Method"] = ["Linear Regression"]
results["RMSE"] = RMSE
results
Method RMSE
0 Linear Regression 14.928334

So from this we would say quite confidently that as age increases so does the bounce time. (To test if this increase is significant see the take home challenge 1.)

However, to run a linear regression a number of assumptions about the data need to be met. One of these is that the residuals are homoscedastic, which means that the residuals are normally distributed in relation to the predicted value, i.e. are our predictions equally bad (or good) across our predicted values. We can look at this by plotting the residuals, using my new favourite package yellowbrick:

#!conda install -c districtdatalabs yellowbrick
import yellowbrick
from sklearn.linear_model import Ridge
from yellowbrick.regressor import ResidualsPlot

# Instantiate the linear model and visualizer
visualizer = ResidualsPlot(model = model)

visualizer.fit(x[:, np.newaxis], y)  # Fit the training data to the model
visualizer.poof()                    # Draw/show/poof the data
../../_images/00-mixed-effect_23_0.png 
<matplotlib.axes._subplots.AxesSubplot at 0x120cd49e8>

Actually not toooooo bad - you could say that there are more positive residuals than negative residuals at the highest and lowest predicted value ranges, e.g. predicted value < 195, and >210 there are more positive residuals than negative. You can have a look at this also using seaborn’s residplot:

ax = sns.residplot(x = "age_scaled", y= "bounce_time", data = data, lowess = True)
ax.set(ylabel='Observed - Prediction')
plt.show()
../../_images/00-mixed-effect_25_0.png

Okay, so perhaps its not ideal…

Let’s check some of the other assumptions. For a good list of the assumptions (with code in R), have a look here http://r-statistics.co/Assumptions-of-Linear-Regression.html.

One of the other key assumption is that the observations of our data are independent of the other data. When we collected our data we were doing it in 8 different counties and in 3 locations within each county. So we could check this by comparing the bounce times for each county. To do this let’s use one of the categorical plots in seaborn:

sns.catplot(x="county", y="bounce_time", data=data, kind = "swarm")

<seaborn.axisgrid.FacetGrid at 0x120ac7f98>
../../_images/00-mixed-effect_27_1.png

Ah… clearly there is substantial grouping - us Londoners seem to have short attention spans (maybe…). So we can definitely say that our data is not independent, and thus it is inappropriate to use a linear model for this data.

What next? Well maybe we could do a separate regression for each county.

Separate Linear Regression#

Same as before, we are going to fit a linear regression to the data, but first separating it by county. Mathematically, this now looks like:

\[ time_c = b_{c0} + b_{c1}age \]

where the subscript c here represents the county. As a result we will be estimating 8 different intercept and 8 different gradients, one for each county. Let’s have a look at that using the facet grid options within sns.lmplot.

# let's use the lmplot function within seaborn
grid = sns.lmplot(x = "age_scaled", y = "bounce_time", col = "county", sharex=False, col_wrap = 4, data = data, height=4)
../../_images/00-mixed-effect_31_0.png

So now we have 8 different analyses. This is fine, but we have started to reduce our sample size a lot already as a result, and we are now perhaps going too far in the other direction from before. Before we were saying that all counties were identical, whereas here we are saying that the impact of age on bounce_time share no similarities between counties, which is probably again not true.

In addition, what about our location variable, maybe our data is also not independent when looking at location. Let’s have a look at this too, using a swarm plot:

sns.catplot(x="location", y="bounce_time", col="county", col_wrap=4, sharey=False, data=data, kind = "swarm")

<seaborn.axisgrid.FacetGrid at 0x1215b46d8>
../../_images/00-mixed-effect_33_1.png

So we could carry on and then do an individual regression for each location within each county… hopefully you can see why we can’t always just do an individual regression for each new group. If we did we would have to to estimate a slope and intercept parameter for each regression. That’s two parameters, three locations and eight counties, which means 48 parameter estimates (2 x 3 x 8 = 48).

Also we would now be taking our nice dataset of 480 observations, that presumably took a long time to collect, and effectively reducing it to lots of sample sizes of 20. This really decreases our statistical power, and thus also increases our chances of a Type I Error (where you falsely reject the null hypothesis) by carrying out multiple comparisons.

So what could we do? Well we could modify the model to account for the different counties, and add it to our linear model.

Modelling county as a fixed effect#

One way to incorporate the impact of county is to bring the county in to our equation for the linear model by treating it as a fixed effect. This would look like:

\[ time_{c_{i}} = b_{0} + b_{1}age + c_i \]

i.e. each county has it’s own additional term that wil change the intercept. To model this we will need to alter our dataframe to encode our counties as numeric variables. So we will use one-hot encoding, where we will make a new column for each county:

# make a new data frame with one hot encoded columns for the counties
counties = data.county.unique()
data_new = pd.concat([data,pd.get_dummies(data.county)],axis=1)
data_new.head()
bounce_time age county location age_scaled cheshire cumbria devon dorset essex kent london norfolk
0 165.548520 16 devon a -1.512654 0 0 1 0 0 0 0 0
1 167.559314 34 devon a -0.722871 0 0 1 0 0 0 0 0
2 165.882952 6 devon a -1.951423 0 0 1 0 0 0 0 0
3 167.685525 19 devon a -1.381024 0 0 1 0 0 0 0 0
4 169.959681 34 devon a -0.722871 0 0 1 0 0 0 0 0 
# construct our linear regression model
model = LinearRegression(fit_intercept=True)
x = data_new.loc[:,np.concatenate((["age_scaled"],counties))]
y = data.bounce_time

# fit our model to the data
model.fit(x, y)

# and let's plot what this relationship looks like 
visualizer = ResidualsPlot(model = model)
visualizer.fit(x, y)  # Fit the training data to the model
visualizer.poof()
../../_images/00-mixed-effect_37_0.png 
<matplotlib.axes._subplots.AxesSubplot at 0x122101390>

# and let's plot the predictions
performance = pd.DataFrame()
performance["residuals"] = model.predict(x) - data.bounce_time
performance["age_scaled"] = data.age_scaled
performance["predicted"] = model.predict(x)

ax = sns.residplot(x = "age_scaled", y = "residuals", data = performance, lowess=True)
ax.set(ylabel='Observed - Prediction')
plt.show()
../../_images/00-mixed-effect_38_0.png

The residuals are much better than before, being more evenly distributed with respect to age, and if we look at the predictions with each county:

data_new["y_predict"] = model.predict(x)
grid = sns.lmplot(x = "age_scaled", y = "y_predict", col = "county", sharey=False, col_wrap = 4, data = data_new, height=4)
grid.set(xlim=(-3,3))

<seaborn.axisgrid.FacetGrid at 0x122766f60>
../../_images/00-mixed-effect_40_1.png 
# and let's store the rmse
y_predict = model.predict(x)
RMSE = sqrt(((y-y_predict)**2).values.mean())
results.loc[1] = ["Fixed", RMSE]
results
Method RMSE
0 Linear Regression 14.928334
1 Fixed 8.563396

Now we can se that the coefficient for the gradient given to age is substantially smaller, and is likely no longer significant. Let’s just check that by making a table of the coefficients:

# coefficient for age and the counties
pd.DataFrame.from_records(list(zip(np.concatenate((["age_scaled"],counties)), model.coef_)))
0 1
0 age_scaled 0.048782
1 devon -21.381957
2 cumbria 9.391460
3 norfolk 9.824419
4 kent 7.938668
5 dorset -2.079637
6 london -21.437323
7 cheshire 18.372916
8 essex -0.628546

But what model have we actually fitted here? Is it what we wanted to investigate initially? The model is estimating the difference in bounce times between the counties now as well, and we aren’t actually interested in that. If you were then this is correct to do so, but the website company just wanted to know whether age affects the bounce times. And by including county in we are obscuring this. So to look at the impact of age on bounce times we need to control for the variation between the different counties (as well as between the locations). So to do that, we have to treat our counties as random effects, and build a mixed effect model!

Mixed effects models#

As we have discussed above, a mixed effects model is ideal here as it will allow us to both use all the data we have (higher sample size) and better acknowledge the correlations between data coming from the counties and locations. We will also estimate fewer parameters and avoid problems with multiple comparisons that we would encounter while using separate regressions.

So in this model we treat our age, which is what we are interested in, as a fixed effect, and county and location as a random effect.

But what does that mean? Well it’s sort of a middle ground here between assuming our coefficient for the gradient and intercept are all the same (what we did in the first regression) and assuming they are all independent and different. If we look back at our equations, we now may assume that while \(b_0\) and \(b_1\) are different for each county, the coefficients all come from a common group distribution, such as a normal distribution:

\[\begin{split} \begin{align*} time_c = b_{c0} + b_{c1}.age \\ \\ b_{c0} \sim N(\mu_{b_0}, \sigma^2_{b_0}) \\ b_{c1} \sim N(\mu_{b_1}, \sigma^2_{b_1}) \end{align*} \end{split}\]

So we now assume the intercepts \(b_0\) and gradients \(b_1\) come from a normal distribution centered around their respective group mean \(\mu\) with a certain standard deviation \(\sigma^2\), the values of which we also estimate.

Fixed vs random?#

So what makes a variable a fixed or random effect. Hmmm, it’s tricky and there are lots of answers out there. In brief, we view fixed effects as the variables that we are interested in. We wanted to know about age so we recorded data on that and wanted to see how it impacted the response variable. County was not we were interested in, but we recorded it as we were aware that our sampling methodology could lead to clustering in our data that could invalidate the linear model from before. If we hadn’t recorded that someone who was given this dataset to analyse may have incorrectly said that age was an important predictor of bounce rate.

Random effects are often our groups we are trying to control for, like county in our example. In particualr twe control for counties when we have not exhausted all the available groups - we only had 8 counties in England. If we wanted to make predicitons about the counties, then we would have tried to sample them better firstly, and also treat them as a fixed effect.

Further reading for those who want a better answer!:

https://dynamicecology.wordpress.com/2015/11/04/is-it-a-fixed-or-random-effect/

And see the discussion in the paper linked in the take home challenge 3.

Fitting our mixed effect lm#

We will now fit our model using the statsmodels library. In this initial model we will look at how the bounce time relates to the scaled ages, while controlling for the impact of counties by allowing for a random intercept for each country, i.e. we are saying that each county has its own random intercept but that the slopes are still the same with respect to age.

import statsmodels.api as sm
import statsmodels.formula.api as smf

# construct our model, with our county now shown as a group
md = smf.mixedlm("bounce_time ~ age_scaled", data, groups=data["county"])
mdf = md.fit()
print(mdf.summary())

          Mixed Linear Model Regression Results
=========================================================
Model:            MixedLM Dependent Variable: bounce_time
No. Observations: 480     Method:             REML       
No. Groups:       8       Scale:              74.7350    
Min. group size:  60      Log-Likelihood:     -1733.0397 
Max. group size:  60      Converged:          Yes        
Mean group size:  60.0                                   
---------------------------------------------------------
             Coef.  Std.Err.   z    P>|z|  [0.025  0.975]
---------------------------------------------------------
Intercept   201.316    5.175 38.902 0.000 191.174 211.459
age_scaled    0.136    0.612  0.221 0.825  -1.065   1.336
Group Var   212.999   13.382                             
=========================================================

In this summary of the model, we can clearly see that the age_scaled is having a more noticable impact than in the fixed model earlier (coefficient of 0.136 rather than 0.048), however, importantly it is still not significantly different to 0, with the 95% interval for this coefficient spanning -1.065 - 1.336.

And let’s look at the predictions.

# and let's plot the predictions
performance = pd.DataFrame()
performance["residuals"] = mdf.resid.values
performance["age_scaled"] = data.age_scaled
performance["predicted"] = mdf.fittedvalues

sns.lmplot(x = "predicted", y = "residuals", data = performance)

<seaborn.axisgrid.FacetGrid at 0x12d68ee80>
../../_images/00-mixed-effect_50_1.png 
ax = sns.residplot(x = "age_scaled", y = "residuals", data = performance, lowess=True)
ax.set(ylabel='Observed - Prediction')
plt.show()
../../_images/00-mixed-effect_51_0.png 
# and let's store the rmse
y_predict = mdf.fittedvalues
RMSE = sqrt(((y-y_predict)**2).values.mean())
results.loc[2] = ["Mixed", RMSE]
results

---------------------------------------------------------------------------
NameError                                 Traceback (most recent call last)
<ipython-input-8-f30f57c37e0b> in <module>()
      1 # and let's store the rmse
      2 y_predict = mdf.fittedvalues
----> 3 RMSE = sqrt(((y-y_predict)**2).values.mean())
      4 results.loc[2] = ["Mixed", RMSE]
      5 results

NameError: name 'y' is not defined

Huh, that’s strange - it’s very similar. In fact the residuals plot looks alomst identical to the previous one where we were treating the county as a fixed effect. Why?

Well, have a think about what we have actually just implemented. All we have done is say in the last one that the county has a randome intercept, but the same slope. This is very similar to the fixed effect approach, where county was included as a term that would impact the intercept. All we have changed is sayng that the intercepts for each county are probably drawn from a similar distribution. To ensure that each county has its own random slope we need to include this in our random effects forumla, like so:

# construct our model, but this time we will have a random interecept AND a random slope with respect to age
md = smf.mixedlm("bounce_time ~ age_scaled", data, groups=data["county"], re_formula="~age_scaled")
mdf = md.fit()
print(mdf.summary())

/Users/gureckis/.virtualenvs/science/lib/python3.7/site-packages/statsmodels/base/model.py:568: ConvergenceWarning: Maximum Likelihood optimization failed to converge. Check mle_retvals
  ConvergenceWarning)
/Users/gureckis/.virtualenvs/science/lib/python3.7/site-packages/statsmodels/regression/mixed_linear_model.py:2202: ConvergenceWarning: Retrying MixedLM optimization with lbfgs
  ConvergenceWarning)
/Users/gureckis/.virtualenvs/science/lib/python3.7/site-packages/statsmodels/base/model.py:568: ConvergenceWarning: Maximum Likelihood optimization failed to converge. Check mle_retvals
  ConvergenceWarning)
/Users/gureckis/.virtualenvs/science/lib/python3.7/site-packages/statsmodels/regression/mixed_linear_model.py:2202: ConvergenceWarning: Retrying MixedLM optimization with cg
  ConvergenceWarning)

               Mixed Linear Model Regression Results
====================================================================
Model:                 MixedLM    Dependent Variable:    bounce_time
No. Observations:      480        Method:                REML       
No. Groups:            8          Scale:                 72.8722    
Min. group size:       60         Log-Likelihood:        -1733.3946 
Max. group size:       60         Converged:             No         
Mean group size:       60.0                                         
--------------------------------------------------------------------
                        Coef.  Std.Err.   z    P>|z|  [0.025  0.975]
--------------------------------------------------------------------
Intercept              202.140    8.356 24.190 0.000 185.762 218.518
age_scaled               0.161    1.196  0.134 0.893  -2.184   2.505
Group Var              558.143                                      
Group x age_scaled Cov -51.614                                      
age_scaled Var           8.621                                      
====================================================================

/Users/gureckis/.virtualenvs/science/lib/python3.7/site-packages/statsmodels/base/model.py:568: ConvergenceWarning: Maximum Likelihood optimization failed to converge. Check mle_retvals
  ConvergenceWarning)
/Users/gureckis/.virtualenvs/science/lib/python3.7/site-packages/statsmodels/regression/mixed_linear_model.py:2206: ConvergenceWarning: MixedLM optimization failed, trying a different optimizer may help.
  warnings.warn(msg, ConvergenceWarning)
/Users/gureckis/.virtualenvs/science/lib/python3.7/site-packages/statsmodels/regression/mixed_linear_model.py:2218: ConvergenceWarning: Gradient optimization failed, |grad| = 7.170191
  warnings.warn(msg, ConvergenceWarning)
/Users/gureckis/.virtualenvs/science/lib/python3.7/site-packages/statsmodels/regression/mixed_linear_model.py:2261: ConvergenceWarning: The Hessian matrix at the estimated parameter values is not positive definite.
  warnings.warn(msg, ConvergenceWarning)

# and let's plot the predictions
performance = pd.DataFrame()
performance["residuals"] = mdf.resid.values
performance["age_scaled"] = data.age_scaled
performance["predicted"] = mdf.fittedvalues

sns.lmplot(x = "predicted", y = "residuals", data = performance)

<seaborn.axisgrid.FacetGrid at 0x12d83b780>
../../_images/00-mixed-effect_55_1.png 
ax = sns.residplot(x = "age_scaled", y = "residuals", data = performance, lowess=True)
ax.set(ylabel='Observed - Prediction')
plt.show()
../../_images/00-mixed-effect_56_0.png 
# and let's store the rmse
y_predict = mdf.fittedvalues
RMSE = sqrt(((y-y_predict)**2).values.mean())
results.loc[3] = ["Mixed_Random_Slopes", RMSE]
results

---------------------------------------------------------------------------
NameError                                 Traceback (most recent call last)
<ipython-input-12-416cac127395> in <module>()
      1 # and let's store the rmse
      2 y_predict = mdf.fittedvalues
----> 3 RMSE = sqrt(((y-y_predict)**2).values.mean())
      4 results.loc[3] = ["Mixed_Random_Slopes", RMSE]
      5 results

NameError: name 'y' is not defined

So our mixed model with the random slopes is now performing much better, with our residuals much better ditributed. Crucially though, we can see that age does not impact the bounce rate, with the confidence intervals for the gradient with respect to age spanning -2.184 - 2.505 after we have controlled for the random variation caused by the county properly, i.e. with a random slope and intercept.

--------------------------------------------------------------------------
                              Coef.  Std.Err.   z    P>|z|  [0.025  0.975]
--------------------------------------------------------------------------
Intercept                    202.140    8.356 24.190 0.000 185.762 218.518
age_scaled                     0.161    1.196  0.134 0.893  -2.184   2.505
Intercept RE                 558.143                              
Intercept RE x age_scaled RE -51.614                                 
age_scaled RE                  8.621                                      
==========================================================================

What we have seen in our data was that individuals in certain counties took longer on the website, and that they happened to also be old. However, to get to this distinction we had to first treat county as a random effect. But what about location? Eh? Forgot about that. See the take home material 4. for that one.